InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If the roots of quadratic equation x2 + px + q = 0 are tan30° and tan15° respectively, then the value of 2+q-p = ....1) 3 2) 4 3) -1 4) -2 |
|
Answer» 1) 3 x2 + px + q = 0 α = tan 30°, β = tan15° α + β = tan 30° + tan15° = -p αβ = tan 30° tan15° = q \(\frac{α+β}{1-ab}=\frac{-P}{1-q}\) \(\frac{tan30°+tan15°}{1-tan30°tan15°}=\frac{-p}{1-q}\) tan 45° = \(\frac{-p}{1-q}\) 1 – q = - p Q – p = 1 2 + q – p = 2 + 1 = 3 |
|