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If the roots of the cubic `x ^(3) +ax ^(2) + bx +c=0` are three consecutive positive integers, then the value of `(a ^(2))/(b +1) =`A. `(a^(2))/(b+a)=3`B. `(a^(2))/(b+a)=1`C. `(b+1)/(a^(2))=3`D. `(c^(2))/(a^(2))=1` |
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Answer» Correct Answer - B::C::D `x^(2)+ax^(2)+bx+c=0larroverset(p-1)underset(p+1)p` `a=-3p` `b=p(p-1)+p(p+1)+(p-1)(p+1)` `c=-p(p-1)(p+1)` `(a^(2))/(b+a)=(9p^(2))/(p^(2)-cancel(p)+p^(2)+cancel(p)+p^(2)-cancel(1)+cancel(1))` `=3` |
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