1.

If the roots of the equation (a-b)x2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c.

Answer»

(a-b)x2 + (b-c) x+ (c - a) = 0
T.P 2a = b + c
B2 – 4AC = 0
(b-c)2 – [4(a-b) (c - a)] = 0
b2-2bc + c2 – [4(ac-a2 – bc + ab)] = 0
 b2-2bc + c2 – 4ac + 4a2 + 4bc - 4ab = 0
 b2+ 2bc + c2 + 4a2 – 4ac – 4ab= 0
 (b + c - 2a)2 = 0
 b + c = 2a



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