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If the roots of the equation \( a x^{2}+b x+c=0 \) are equal then \( c=? \)\( 58 \quad \) 1) \( -\frac{b}{2 a} \)2) \( \frac{b}{2 a} \)3) \( -\frac{b^{2}}{4 a} \)4) \( \frac{b^{2}}{4 a} \) |
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Answer» b2 -4ac = 0 ( as roots are equal to discriminant is equal to zero) b2 = 4ac b2/4a = c
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