1.

If the roots of the equation x^(2)+2bx+c=0 are alpha" and "beta, " then "b^(2)-c =

Answer»

`((ALPHA - BETA)^2)/(4)`
`(alpha + beta)^(2)- alpha beta`
`(alpha + beta)^(2)+ alpha beta`
`((alpha + beta)^2)/(4)- alpha beta`

ANSWER :A


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