If the selling price of 16 water bottles is equal to the cost price of

1.	If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain percent earned by the dealer.
Answer» Let us consider the CP of 17 water bottles = ₹100 ∴ The CP of 17 water bottles = SP of 16 water bottles = ₹100 SP of 17 water bottles = (100/16) × 17 = ₹106.25 Since, SP is more than CP so it’s a gain. Gain = SP – CP = 106.25 – 100 = ₹6.25 Gain % = (Gain × 100) / CP = (6.25 × 100) / 100 = 6.25% ∴ The Gain percent is 6.25%

If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain percent earned by the dealer.

Answer»

Let us consider the CP of 17 water bottles = ₹100

∴ The CP of 17 water bottles = SP of 16 water bottles = ₹100

SP of 17 water bottles = (100/16) × 17 = ₹106.25

Since, SP is more than CP so it’s a gain.

Gain = SP – CP = 106.25 – 100 = ₹6.25

Gain % = (Gain × 100) / CP

= (6.25 × 100) / 100

= 6.25%

∴ The Gain percent is 6.25%