1.

If the series limit wavelength of the Lyman series for hydrogen atom is `912 Å`, then the series limit wavelength for the Balmer series for the hydrogen atom is

Answer» For series limit of Balmer series, we can write,
`n_(2)=2,n_(1)=oo`
`rArr " " (1)/(lambda)=R((1)/(n_(2)^(2))-(1)/(n_(1)^(2)))=R[(1)/((2)^(2))-(1)/((oo)^(2))]=(R)/(4)`
`:. " " lambda=(4)/(R) =(4)/(10967800)=4xx912xx10^(-10)m`
`=4xx912Å=3648Å`


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