If the shortest wavelength of spectral line of H-atom in Lyman series is x. Then match the following for Li^(2+)

If the shortest wavelength of spectral line of H-atom in Lyman series

1.	If the shortest wavelength of spectral line of H-atom in Lyman series is x. Then match the following for Li^(2+)
Answer» Solution :`1/(lambda) = R_H Z^2 [1/(n_1^2) - 1/(n_2^2)]` `Li^(2+) (Z=3) `, For Lyman SERIES `lambda_("max") , n_2 = 2 ` `lambda_("MIN") , n_2 = OO`