If the side of a cube is increased by 50%, then the total surface area

1.	If the side of a cube is increased by 50%, then the total surface area is increased by:1. 50%2. 75%3. 100%4. 125%
Answer» Correct Answer - Option 4 : 125% Given: The side of a cube is increased by 50% Concept used: The total surface area of a cube with side 'a' = 6 × a² Calculation: The total surface area of a cube with side 'a', = 6a² ⇒ S = 6 × a2 New length of the side = a × 150% = 3a/2 The total surface area of the new cube with side '3a/2', ⇒ S_N= 6 × (3a/2)² ⇒ SN = 6 × a² × (3/2)² ⇒ S_N= S × 9/4 ⇒ S_N/S = 9/4 Increase in total surface area = (SN - S)/S × 100 ⇒ (9 - 4)/4 × 100 ⇒ 125% ∴ The total surface area increased by 125%.

If the side of a cube is increased by 50%, then the total surface area is increased by:1. 50%2. 75%3. 100%4. 125%

Answer» Correct Answer - Option 4 : 125%

Given:

The side of a cube is increased by 50%

Concept used:

The total surface area of a cube with side 'a' = 6 × a²

Calculation:

The total surface area of a cube with side 'a', = 6a²

⇒ S = 6 × a2

New length of the side = a × 150% = 3a/2

The total surface area of the new cube with side '3a/2',

⇒ S_N= 6 × (3a/2)²

⇒ SN = 6 × a² × (3/2)²

⇒ S_N= S × 9/4

⇒ S_N/S = 9/4

Increase in total surface area = (SN - S)/S × 100

⇒ (9 - 4)/4 × 100

⇒ 125%

∴ The total surface area increased by 125%.

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