1.

If the sixth term of an AP is zero then show that its 33rd term is three times its 15th term.

Answer» a +5d =0 `rArr` a = -5d.
33th term = a +32d = -5d +32d = 27d
3(15th term) = 3(a+14d) = 3(-5d+14d) = `3 xx9d` = 27d


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