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If the sixth term of an AP is zero then show that its 33rd term is three times its 15th term. |
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Answer» a +5d =0 `rArr` a = -5d. 33th term = a +32d = -5d +32d = 27d 3(15th term) = 3(a+14d) = 3(-5d+14d) = `3 xx9d` = 27d |
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