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If the size of a nucleus `(~~10^(-15)m)` is scaled up to the tip of a sharp pin `(~~ 10^(-5)m),` what roughly is the size of an atom? |
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Answer» `"Magnification" = ("size of tip of pin")/("size of nucleus")` `=10^(-5)/(10^(-15)) = 10^(10)` `"As actual size of atom" `~~ 10^(-10)m` `"and it is magnified" 10^(10)` times, :. `"Apparent size of atom" = 10^(10) xx10^(10)` `=10^0 = 1m` |
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