1.

If the size of a nucleus `(~~10^(-15)m)` is scaled up to the tip of a sharp pin `(~~ 10^(-5)m),` what roughly is the size of an atom?

Answer» `"Magnification" = ("size of tip of pin")/("size of nucleus")`
`=10^(-5)/(10^(-15)) = 10^(10)`
`"As actual size of atom" `~~ 10^(-10)m`
`"and it is magnified" 10^(10)` times,
:. `"Apparent size of atom" = 10^(10) xx10^(10)`
`=10^0 = 1m`


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