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InterviewSolution
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If the slopes of the lines given by `ax^(2)+2hxy+by^(2)=0` are in the ratio `3:1`, then `h^(2)=`A. `(ab)/(3)`B. `(4ab)/(3)`C. `(4a)/(3b)`D. none of these |
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Answer» Correct Answer - B Let `y=m_(1)x and y=m_(2)x` be the lines represented by the given equation. Then, `m_(1)+m_(2)=-(2h)/(b)and m_(1)m_(2)=(a)/(b)` We have, `m_(1):m_(2)=3:1rArrm_(1)=3m_(2)` `therefore" "m_(1)+m_(2)=-(2h)/(b)and m_(1)m_(2)=(a)/(b)` `rArr" "4m_(2)=-(2h)/(b) and 3m_(2)^(2)=(a)/(b)` `rArr" "m_(2)=-(h)/(2b)and 3m_(2)^(2)=(a)/(b)` `rArr" "3(-(h)/(2b))^(2)=(a)/(b)rArr h^(2)=(4ab)/(3)` |
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