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If the solubility of `Ag_(2)CrO_(4)` is S mol/L, its solubility product will beA. `S^(2)`B. `S^(3)`C. `4S^(3)`D. `2S^(3)` |
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Answer» Correct Answer - C `underset(S mol//L)(Ag_(2)CrO_(4)) hArr underset(2s)(2Ag^(+))+underset(S)(CrO_(4)^(2-))` `K_(sp) = [Ag^(+)]^(2)[CrO_(4)^(2-)]` `=(2S)^(2) (S) = 4S^(3)` |
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