Saved Bookmarks
| 1. |
If the solubility of zirconium phosphate is x, what is its solubility product? What are the units of solubility product of Zr_3 (PO_4 )_4? |
|
Answer» Solution :Zirconium phosphate DISSOCIATES in aqueous solutions as `Zr_3 (PO_4)_4 hArr+3Zr^(4+)+ 4PO_(4)^(3-)` If x is the solubility, `[Zr^(4+)] =3S and [PO_(4)^(3-) ] = 4S` The solubility product `K_(sp)` is `Kp_(sp)= [Zr^(4+)] [PO_(4)^(3-) ]^4 =(3s)^2 (4s)^4 = 6912 s^7` The units of solubility product are : `mol^7L^(-7)` |
|