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If the solubility product of `CuS` is `6xx10^(-16)`, calculate the maximum molarity of `CuS` in aqueous solution. |
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Answer» Correct Answer - `S=2.45xx10^(-8)mol^(-1)` Maximum molarity of `CuS` in aqueous solution is the solubility of `CuS` in `mol L^(-1)`. Let `S` is the solubility of `CuS` in `mol L^((-1)`, then `CuS hArr Cu^(2+)+S^(2-)` `K_(sp)=[Cu^(2+)][S^(2-)]` `=SxxS` ltbr. `=S^(2) mol^(2)L^(-2)` `:. S=sqrt(K_(sp))=sqrt(6xx10^(-16))` `2.45xx10^(-8)mol L^(-1)` |
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