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If the solubility product of silver chloride is 1.8xx10^(-10). What is the solubility of silver ion if concentration of Cl^(-) is 0.01 molar. |
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Answer» Solution :`K_(sp)=[Ag^(+)][CL^(-)]""1.8xx10^(-10)=[Ag^(+)]0.01` `[Ag^(+)]=(1.8xx10^(-10))/(0.01)=180xx10^(-10)=1.8xx10^(-8)"MOL"//dm^(3)` |
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