1.

If the solubility product of silver chloride is 1.8 × 10-10. What is the solubility of silver ion if concentration of Cl– is 0.01 molar.

Answer»

Ksp = [Ag+][Cl-]

1.8 x 10-10 = [Ag+]0.01

[Ag+] = \(\frac{1.8\times 10^{-10}}{0.01}\) = 180 x 10-10

= 1.8 x 10-8 mol/dm3



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