1.

If the speed of a vehicle become 3 times for a given deceleration its stopping distance become .....

Answer»

two
three
nine
four

SOLUTION :2a is equaliristoppingdistance`d = (v_(0)^(2))/(2 a)`
`PROP v_(0)^(2)`
`(d_(2))/(d_(1))= ((v_(0))_(2)^(2))/((v_(0))_(1)^(2)) = (3v_(0))/(v_(0)) = (3)^(2) `= nine


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