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If the speed of light is 3.0 xx 108 m s^(–1), calculate the distance covered by light in 2.00 ns. |
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Answer» Solution :Distance COVERED = speed `XX` time `=3.0 xx 10^(8) MS^(-1)xx 2.00 s` `=3.0 xx 10^(80) ms^(-1) xx 2.00 ns xx (10^(-9) s)/(1 ns)=6.00 xx 10^(-1) m = 0.600 m` |
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