1.

If the speed of light is 3.0xx10^(8) ms^(-1), calculate the distance covered by light in 2.00 ns.

Answer»



Solution :`2 ns = 2.00xx10^(-8)s`
Distance `= "speed " xx "TIME"`
`=3XX10^(8) ms^(-1) xx 2.0 xx 10^(-9)s`.
`=6.0xx10^(-1) m = 0.6 m`


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