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If the speed of the particle is v=4t3−3t2+3 m/s, the distance of the particle as a function of time t and the average speed in 2 sec respectively are |
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Answer» If the speed of the particle is v=4t3−3t2+3 m/s, the distance of the particle as a function of time t and the average speed in 2 sec respectively are |
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