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If the sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers, then k =(a) 1n(b) n-1n(c) n+12n(d) n+1n |
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Answer» If the sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers, then k = (a) (b) (c) (d) |
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