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If the sum of n terms of an A.P is cn (n-1)where `c ne 0` then the sum of the squares of these terms isA. `c^2n(n+1)^2`B. `2/3c^2n(n-1)(2n-1)`C. `(2c^2)/(3)n(n+1)(2n+1)`D. none of these |
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Answer» Correct Answer - B If `t_(r)` be the rth term of the A.P., then `t_(r)=S_(r)-S_(r-1)` `=cr(r-1)-c(r-1)(r-2)` `=c(r-1)(r-r+2)-2c(r-1)` We have, `t_(1)^(2)+t_(2)^(2)+…+t_(n)^(2)=4c^(2)(0^(2)+1^(2)+2^(2)+…+(n-1)^(2))` `=4c^(2)((n-1)n(2n-1))/6` `=2/3c^2n(n-1)(2n-1)` |
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