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If the sum of squares of three consecutive natural number is 2702. Then, what will be the middle number?1). 292). 303). 314). 32 |
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Answer» Solution: Let us take the there consecutive natural numbers as x ,(x +1) and (x + 2). It is given that, The sum of squares of three consecutive natural numbers= 2702 So, x² + (x + 1)² + (x + 2)² = 2702 x² + x² + 1 + 2x + x² + 4 + 4X = 2702 3x² + 6x + 5 = 2702 3x² + 6x = 2702 - 5 3x² + 6x = 2697 Dividing the whole EQUATION by three we get, x² + 2x - 899 = 0 (x - 29)(x + 31) = 0 So, x = 29 So, the middle term,(x + 1) = 30 So, the correct option is 2). 30 |
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