1.

If the sum of squares of three consecutive natural number is 2702. Then, what will be the middle number?1). 292). 303). 314). 32

Answer»

Solution:

Let us take the there consecutive natural numbers as x ,(x +1) and (x + 2).

It is given that,

The sum of squares of three consecutive natural numbers= 2702

So, x² + (x + 1)² + (x + 2)² = 2702

x² + x² + 1 + 2x + x² + 4 + 4X = 2702

3x² + 6x + 5 = 2702

3x² + 6x = 2702 - 5

3x² + 6x = 2697

Dividing the whole EQUATION by three we get,

x² + 2x - 899 = 0

(x - 29)(x + 31) = 0

So, x = 29

So, the middle term,(x + 1) = 30

So, the correct option is 2). 30



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