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If the sum of the distances of a point from two perpendicular lines in a plane is 1, then prove that its locus is a square. |
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Answer» Take the two perpendicular lines as coordinate axes. P(x, y) is a point on the locus ⇔|x| + |y| = 1. This implies that x + y = 1 x - y = 1 -x + y = 1 -x - y = 1 These lines form a square. |
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