If the sum of the first pterms of an AP is ap +bp, find its common dif

1.	If the sum of the first pterms of an AP is ap +bp, find its common difference.
Answer» Given, sum of first P termsSp = ap^2 + bp. Then sum of first two terms.S2 = a(22) + b2 = 4a + 2b First term of an APt1 = a(1*1) + b(1)4 3 = a + b Second term of an APt2 = (4a + 2b) - (a + b) = 3a + b Common difference= t2 - t1= (3a + b) - (a + b)= 2a

If the sum of the first pterms of an AP is ap +bp, find its common difference.

Answer»

Given, sum of first P termsSp = ap^2 + bp.

Then sum of first two terms.S2 = a(2*2) + b*2 = 4a + 2b

First term of an APt1 = a(1*1) + b(1)4 3 = a + b

Second term of an APt2 = (4a + 2b) - (a + b) = 3a + b

Common difference= t2 - t1= (3a + b) - (a + b)= 2a