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If the sum of the roots of the equation x2 – (k + 6)x + 2 (2k – 1) = 0 is equal to half of their product, then k =A. 6 B. 7 C. 1 D. 5 |
Answer» In the given equation x2 – (k + 6)x + 2 (2k – 1) = 0 a = 1, b = – (k + 6), c = 2 (2k – 1) Sum of the roots = 1/2 (product of roots) (given) K + 6 = 2k – 1 K = 7 |
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