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If the sum of the zeroes of the quadratic polynomial f(t) = kt2 + 2t + 3k is equal to their product, then find the value of k. |
Answer» Given, The quadratic polynomial f(t) = kt2 + 2t + 3k, where a = k, b = 2 and c = 3k. And, Sum of the roots = Product of the roots ⇒ (-b/a) = (c/a) ⇒ (-2/k) = (3k/k) ⇒ (-2/k) = 3 ∴ k = -2/3 |
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