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if the sum of three numbers in an ap is 9 and their product is 24 then numbers are |
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Answer» Let three numbers be a - d, a, a + d ∴ a - d +a + a + d = 9 ⇒ 3a = 9 ⇒ a = 3 Also (a - d) × a × (a + d) = 24 ⇒ (3 - d) × 3(3 + d) = 24 ⇒ 9 - d2 = 8 ⇒ d2 = 9 - 8 = 1 ∴ d = ± 1 Hence numbers are 2, 3, 4 or 4, 3, 2 |
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