1.

If the Sum of three. numbers of an arithmetic sequence és 15 and the sum of their squares is then the numbers are 83, (a) 4,5,6

Answer»

Let a-d, a, a+d are the three numbers.

Then sum = a-d+a+a+d = 15

3a = 15

a = 5

Sum of squares, (a-d)2+a2+(a+d)2 = 83

a2-2ad+d2+a2+a2+2ad+d2 = 83

3a2+2d2 = 83

Substitute a = 5

75+2d2 = 83

2d2 = 8

d2 = 4

So d = 2

Then the numbers are 3, 5, 7.



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