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If the sum of two numbers is 66 and the H.C.F and L.C.M of the numbers are 6 and 120 respectively, then the sum of the reciprocals of numbers is equal to∶1). 11/1202). 21/1203). 15/1304). 55/120 |
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Answer» LET the numbers are x and y Then, x + y = 66 We know that, LCM × HCF = Product of TWO numbers ⇒ xy = 6 × 120 = 720 ∴ REQUIRED sum $(= \frac{1}{{\rm{x}}} + \frac{1}{{\rm{y}}} = \frac{{\left( {{\rm{x\;}} + {\rm{\;y}}} \right)}}{{{\rm{xy}}}} = \frac{{66}}{{720}} = \frac{{11}}{{120}})$ |
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