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if the sum off two number is 33 and their difference is 15. find the smallest numbers |
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Answer» x+y=33x-y=152x=48x=24y=9so smallest no. is 9 Let the numbers be x&yx+y=33..........(1)x-y=15.............(2)(1)+(2)=>2x=48=>x=24now substituting x in (1) ,we get,y=9the smallest number is y which equals to9 x + y = 33x - y = 152× = 48× = 48/2x = 24So y = 24 - 15 = 9So smaller number is 9 x + y = 33, ; x - y = 15; x - y = 15/ 2y =18; y = 18/2 = 9; x = 15 +9=24; smallest number = 9; x+y=33x-y=152x=48x=24so y=24-15 =9so small er number is 9 let there be two variable x and yas per questionx+y =33x-y= 15adding above equation 2x= 48x=24therefore y = 9hence the smaller number is 9 |
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