Saved Bookmarks
| 1. |
If the surface tension of solution of soap in water is 35 dynes/cm, calculate the work done to form one air bubble of diameter 14 mm with that solution. |
|
Answer» Solution :Surface tension T = 35 dynes `cm^(-1)=0.035Nm^(-1)` RADIUS of the bubble (r ) = `(14mm)/2=7mm=7xx10^(-3)m` Total surface area of the bubble formed `A=2xx4pir^(2)` `rArrA=2xx4xx22/7xx(7xx10^(-3))^(2)=1.232xx10^(-3)m^(2)` Work DONE to FORM the SOAP bubble W = A(T) `rArrW=1.232xx10^(-3)xx0.035J,W=4.312xx10^(-5)J` |
|