If the surface tension of water is 0.06 Nm^(-1), then the capillary rise in a tube of diameter 1 mm is (angle of contact = 0^@) ………….. .

If the surface tension of water is 0.06 Nm^(-1), then the capillary ri

1.	If the surface tension of water is 0.06 Nm^(-1), then the capillary rise in a tube of diameter 1 mm is (angle of contact = 0^@) ………….. .
Answer» 1.22 cm 2.44 cm 3.12 cm 3.86 cm Solution :`h = (2T cos theta)/(r rho G) = (2 XX 0.06 xx 1)/(0.5 xx 10^(-3) xx 9.8) = 0.0244 m implies h = 2.44 cm`.