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If the system is suspended by the mass m the length of the spring is `l_(1)`. If it is inverted and hung by mass M, the length of the spring is `l_(2)`. Find the natural length of the spring. A. `(ml_(1)+Ml_(2))/(m+M)`B. `(ml_(2)+Ml_(1))/(m+M)`C. `(ml_(1)-Ml_(2))/(m-M)`D. `(ml_(2)-Ml_(1))/(m-M)` |
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Answer» Correct Answer - C `k(l_(1)-l_(0))=Mg` `k(l_(2)-l_(0))=mg` `(l_(1)-l_(0))/(l_(2)-l_(0))=M/m` `ml_(1)-ml_(0) =Ml_(2)-Ml_(0)` `l_(0)=(ml_(1)-Ml_(2))/(m-M)` |
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