1.

If the temperature of a uniform steel rod of mass 12 kg and length 1 m is increased by 20 ∘C, its moment of inertia about its perpendicular bisector increases by - [ α=11×10−6/ ∘C ]

Answer»

If the temperature of a uniform steel rod of mass 12 kg and length 1 m is increased by 20 C, its moment of inertia about its perpendicular bisector increases by -
[ α=11×106/ C ]



Discussion

No Comment Found

Related InterviewSolutions