1.

If the three lines x-3y=p.ax+2y=q and ax+y=r from a right - angled triangle then.

Answer»

`a^(2)-6a-12=0`
`a^(2)-9a+12=0`
`a^(2)-9a+18=0`
`a^(2)-6a-18=0`

Solution :EQUATION `x=3y=-` and `ax+y=4` are only possible to form a RIGHT ANGLE triangle
`:.` value of `a=3`
satisfy the equation `a^(2)-9a+18=0`


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