1.

If the three lines x – 3y = p, ax + 2y = q and ax + y = r from a right – angled triangle then:

Answer»

`a^2-6a-12=0`
`a^2-9a+12=0`
`a^2-9a+18=0`
`a^2-6a-18=0`

Solution :EQUATION x-3y=p and AX +=r are only POSSIBLE to FORM a RIGHT angle triangle
`therefore` value of a=3
satisfy the equation `a^2 - 9a +18=0`


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