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If the total charge stored in the `LC` circuit is `Q_(0)`, then for `tgt= 0`A. the charge on the capacitor is `Q=Q_(0) cos(pi/2+t/sqrt(LC))`B. the charge on the capacitor is `Q=Q_(0) cos(pi/2-t/sqrt(LC))`C. the charge on the capacitor is `Q=-LC(d^(2)Q)/(dt^(2))`D. the charge on the capacitor is `Q=-1/sqrt(LC)(d^(2)Q)/(dt^(2)` |
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Answer» Correct Answer - C `Q-Q_(0) cosomegat …(1)` `(dQ)/(dt)=-Q_(0)omegasinomegat implies(d^(2)Q)/(dt^(2))=-Q_(0)omega^(2) cosomegat…(2)` From `(1)` and `(2)` `(d^(2)Q)/(dt^(2))=-omega^(2)Q` `implies Q=-1/omega^(2)(d^(2)Q)/(dt^(2))=-LC(d^(2)Q)/(dt^(2))` |
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