1.

If the two circles x^(2)+y^(2)+2gz+2fy=0 and x^(2)+y^(2)+2g'x+2f'y=0 touch each other then show that f'g=fg'

Answer»

`FG=F^(1)g^(1)`
`fg^(1)=f^(1)g`
`f+g=f^(1)+g^(1)`
`f+f^(1)=g+g^(1)`

ANSWER :B


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