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If the uncertainty in the position of a moving electron is equal to its de Broglie wavelength, then its velocity will be completely uncertain. Explain. |
Answer» According to available information , `Deltax=lambda` But ` lambda =(h)/(mv) =(h)/(p) :. P=(h)/(lambda)=(h)/(Deltax) or Delta x =(h)/(p)` According to uncertainty principle, `DeltaxDeltap ge (h)/(4pi)`. `:. " " (h)/(p) Deltap ge (h)/(4 pi) or (Deltap)/(p) ge (1)/(4 pi)` (constant) This means that `Deltap ge p or m DeltaV ge mV or DeltaV ge V`. This means that the velocity of electron will be completely uncertain. |
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