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If the uniform electric field is `3xx10^(3)hatiNC^(-1)`, then the flux of this field through a square of 10 cm on a side whose plane is parallel to the y-z- plane gt?A. `30Nm^(2)C^(-1)`B. `60Nm^(2)C^(-1)`C. `15Nm^(2)C^(-1)`D. `25Nm^(2)C^(-1)` |
Answer» Correct Answer - A Here `E=3xx10^(3)hatiNc^(-1)` Field is along positive direction of X-axis Surface are `S=(10)^(2)cm^(2)=10^(-2)m^(2)` When plane is parallel to YZ - plane, `theta=0^(@)` `phi_(E)=ES cos theta=3xx10^(3)xx10^(-2)cos theta=30Nm^(2)C^(-1)` |
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