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If the unit digit of 433 × 456 × 43N is (N + 2), then what is the value of N?1). 12). 83). 34). 6 |
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Answer» If N = 1 ⇒ 433 × 456 × 431 ⇒ Last digit = 8(By multiplying last digits of all 3 number) SINCE N + 2 ≠ 8, it will not SATISFY the GIVEN condition. If N = 8 ⇒ 433 × 456 × 438 ⇒ Last digit = 4, it will also not satisfy the given condition. If N = 3 ⇒ 433 × 456 × 433 ⇒ Last digit = 4, it will also not satisfy the given condition. If N = 6 ⇒ 433 × 456 × 436 ⇒ Last digit = 8 = (N + 2) ∴ N = 6 will satisfy the given condition. |
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