1.

If the unit digit of 433 × 456 × 43N is (N + 2), then what is the value of N?1). 12). 83). 34). 6

Answer»

CHECK with OPTIONS:

If N = 1

⇒ 433 × 456 × 431

⇒ Last digit = 8(By multiplying last digits of all 3 number)

SINCE N + 2 ≠ 8, it will not SATISFY the GIVEN condition.

If N = 8

⇒ 433 × 456 × 438

⇒ Last digit = 4, it will also not satisfy the given condition.

If N = 3

⇒ 433 × 456 × 433

⇒ Last digit = 4, it will also not satisfy the given condition.

If N = 6

⇒ 433 × 456 × 436

⇒ Last digit = 8 = (N + 2)

∴ N = 6 will satisfy the given condition.


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