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If the value of equilibrium constant `K_(c)` for the reaction, `N_(2)+3H_(2)hArr2NH_(3)` is 7. The equilibrium constant for the reaction `2N_(2)+6H_(2)hArr4NH_(3)` will beA. 49B. 7C. 14D. 28 |
Answer» Correct Answer - A If reaction is multiplied by 2, the equilibrium constant becomes square of the previous value. `K=7^(2)=49` |
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