1.

If the value of equilibrium constant `K_(c)` for the reaction, `N_(2)+3H_(2)hArr2NH_(3)` is 7. The equilibrium constant for the reaction `2N_(2)+6H_(2)hArr4NH_(3)` will beA. 49B. 7C. 14D. 28

Answer» Correct Answer - A
If reaction is multiplied by 2, the equilibrium constant becomes square of the previous value.
`K=7^(2)=49`


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