InterviewSolution
Saved Bookmarks
| 1. |
If the value of "^(n)C_(0)+2*^(n)C_(1)+3*^(n)C_(2)+...+(n+1)*^(n)C_(n)=576,then n is |
|
Answer» Solution :`(a)` `S=^(N)C_(0)+2.^(n)C_(1)+3.(n)C_(2)+...+(n+1).^(n)C_(n)` Here `T_(r )=(r+1)^(n)C_(r )=n^(n-1)C_(r-1)+^(n)C_(r )` `:.S=n^(2n-1)+2^(n)=576` (given) `:.n=7` |
|