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If the variance of first n natural numbers is 2 and the variance of first m odd natural numbers is 40, then m+n =

Answer»


Solution :Variance of first N natural numbers is `(n^2-1)/12=2 RARR n^2=25 rArr n=5`
variance of first m ODD natural numbers is
`2^2 ((m^2-1))/12=40 rArr (m^2-1)/12=10`
`rArr m^2-1 =120 rArr m^2=121 rArr` m=11


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