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If the vectors hat(i)-3hat(j)+2hat(k), -hat(i)+2hat(j) represent the diagonals of a parallelogram, then its area will be |
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Answer» `sqrt(21)` Now, `axxb=|{:(hati,hatj,HATK),(1,-3,2),(-1,2,0):}|=-4hati-2hatj-hatk` `:.""` AREA of parallelogram `=1/2|axxb|=1/2sqrt(16+4+1)=sqrt(21)/2` |
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