If the veemaindue of (om +1) (5m+3) (5mis a natural number, then find

1.	If the veemaindue of (om +1) (5m+3) (5mis a natural number, then find it
Answer» When ,(5m+1)(5m+3(5m+4) 5=5m(5m+3)(5m+4) + 1(5m+3)(5m+4) 5 =5m(5m+3)(5m+4) + 5m(5m+4) + 3(5m+4) 5={ m(5m+3)(5m+4) + m(5m+4) +15m + 12}/5 = {m(5m+3)(5m+4) + m(5m+4) + 3m + 12}/5 The remainder of 12/5 is 2, so the remainder of (5m+1)(5m+3)(5m+4)/5 is 2.

If the veemaindue of (om +1) (5m+3) (5mis a natural number, then find it

Answer»

When ,(5m+1)(5m+3(5m+4) 5=5m(5m+3)(5m+4) + 1(5m+3)(5m+4) 5

=5m(5m+3)(5m+4) + 5m(5m+4) + 3(5m+4) 5={ m(5m+3)(5m+4) + m(5m+4) +15m + 12}/5 = {m(5m+3)(5m+4) + m(5m+4) + 3m + 12}/5

The remainder of 12/5 is 2, so the remainder of (5m+1)(5m+3)(5m+4)/5 is 2.