Saved Bookmarks
| 1. |
If the velocity of light is taken as the unit of velocity and year as the unit of time find the unit of length? |
|
Answer» SOLUTION :Dimensional formula for velocity is `v=[LT^(-1)]` `n_(1)[L_(1)T_(1)^(-1)]=n_(2)[L_(2)T_(2)^(-1)]` `L_(2)=((n_(1))/(n_(2)))((T_(1))/(T_(2)))^(-1)L_(1)`..i Here `n_(1)` is the numerial value of velocity in the system where unit of length is `L_(1)` and that TIME is `T_(1)` and `n_(2)` is the numerical value of velocity in the system where unit of length is `L_(2)` and that of time is `T_(2)`. `n_(1)=3xx10^(8)""L_(1)=1m, ""T_(1)=1s` `n_(2)=1""L_(2)=?""T_(2)=1"year"=365.25xx24xx60xx60s` Substituting these values in equation (i) `L_(2)=((3xx10^(8))/1)(1/(365.25xx24xx60xx60))^(-1)`(1) `=3xx10^(8)xx365.25xx24xx60xx60=9.468xx10^(15)m` This unit of length is called a light year. |
|