1.

If the velocity of the electron in Bohr's first orbit is 2.19 xx 10^(6) m s^(-1), calculate the de Broglie wavelength associated with it.

Answer»

SOLUTION :`lamda = (H)/(MV) = (6.626 XX 10^(-34) kg m^(2) s^(-1))/((9.11 xx 10^(-31) kg) (2.19 xx 10^(6) ms^(-1))) = 3.32 xx 10^(-10) m = 332` pm


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